Video Lectures

Theory For Notes Making

 

Introduction

Kinematics is that branch of mechanics, which describes the motion of bodies without reference to the forces that either cause the motion or are generated as a result of the motion.  Kinematics is often referred to as the ‘geometry of motion’.

Rest And Motion

An object is said to be in motion if its position changes with respect to its surroundings with time. On the other hand, if the position of the object does not change with respect to its surroundings, it is said to be at rest. A car speeding on the road, a ship sailing on water and a bird flying in air are examples of objects in motion. A book lying on a table is at rest because its position with respect to the table does not change with time.

Dimensions In Motion

The motion of an object is said to be one dimensional when only one of the three coordinates specifying the position of the object changes with time. The motion of a car on a road, the motion of a train along a railway track or an object falling freely are examples of one dimensional motion. One dimensional motion is also termed as rectilinear motion. The motion of an object  is said to be two dimensional when two of the three coordinates specifying the position of the object change with time. The motion of a planet around the sun, a body moving along the circumference of a circle are examples of motion in two dimensions. Two dimensional motion is also referred to as motion in a plane.

Trajectory

The actual path followed by an object in a particular reference frame is termed as its “trajectory”. Thus, the trajectory is a straight line in case of one dimensional motion whereas in case of a two dimensional motion, the trajectory may be a circle, a parabola or in general, any curve.

Displacement And Distance

Displacement

Distance

1.

The displacement  of a particle is defined as the difference between its final position and its initial position. We represent the displacement as Dx.

                Dx = xf xi

2.     

Displacement is a vector  quantity which has both magnitude and direction.

3.   

It can increase and decrease with time.

4.

Depending on direction it can be positive or negative.

1.   

The length of the actual path covered by a body in a time interval is called distance.

2.     

Distance is a scalar quantity which has magnitude only

3.     

It never decreases with time.

4.     

It is always positive

Average Velocity and Average Speed

The average velocity of an object  is defined as the ratio of its displacement to the time taken for that displacement

                 vav= \frac{{\Delta x}}{{\Delta t}}\,=\frac{{{{x}_{f}}-{{x}_{i}}}}{{{{t}_{f}}-\,{{t}_{i}}}}

The average speed of a particle is defined as the ratio of the total distance travelled to the time taken

Average speed = \displaystyle \frac{{Total\,\,distance\,\,travelled}}{{\Delta t}}

Note that:  velocity and speed have different meanings. Velocity is a vector and speed is a scalar

Instantaneous Speed and Instantaneous Velocity

Instantaneous velocity  is defined as the value approached by the average velocity when the time interval for measurement becomes closer and closer to zero, i.e. Δt → 0

Mathematically

       v(t) =           \underset{{\Delta t\to \,0}}{\mathop{{lim}}}\,\,{{v}_{{av}}}\,=\,\underset{{\Delta t\to \,0}}{\mathop{{lim}}}\,\,\frac{{\Delta x}}{{\Delta t}}

The instantaneous velocity function is the derivative of the displacement function with respect to the time 

   v(t) = \frac{{dx(t)}}{{dt}}

Graphical Analysis of Motion along a straight line

Average Velocity

The average velocity between two points in a given time interval can be obtained from a displacement versus-time graph by computing the slope of the straight line joining the coordinates of the two points.

Instantaneous Velocity

The instantaneous velocity at time t is the slope of the tangent line drawn to the position-versus-time graph at that time.

The position (x) versus time (t) graph of a particle whose velocity is not constant is shown in the diagram given below. In a given time interval Dt the slope of the chord joining two points on the curve gives the average velocity of the particle for that time interval. Whereas the instantaneous velocity at any point of time is equal to the slope of the tangent at that  point on the curve.

Note :The direction of instantaneous velocity may be different from direction of average velocity

Uniform Motion in a Straight Line

A body is said to be in a uniform motion if it travels equal distance in equal intervals of time along a straight line.

A position(x) Vs time (t)  graph for uniform motion is a straight line.

e.g., A vehicle running in a certain direction with the constant speed of 10 m/s will cover equal distances of 10 m in every second, so its motion will be uniform

For a uniform motion along a straight line in a given direction, the magnitude of the displacement is equal to the actual distance covered by the object.

Calculation Of Displacement and Distance

Case-1

When the body is  in uniform motion The displacement and distance can be calculated very easily by simple relations

\displaystyle \text{Distance = Displacement = v}\times \text{t}

Since in uniform motion the direction of body remains fixed so we don’t bother about the direction.

Case-2

When the body reverses its direction and changes its speed instantly at the time of changing the direction. 

For example the body moves for time t1 in the positive x direction with speed v1 and then for time t2 it moves along the negative x direction with speed v2.

So Distance =  v1.t +  v2.t2 

and Displacement = v1.t –  v2.t2

Illustration

Look at the graphs (a) to (d) carefully and state with reasons, which of these cannot possibly represent one-dimensional motion of a particle

Solution

(a) No, graph (a) is not representing one-dimensional motion of a particle, because graph shows two different positions of the particle at same instant of time. 

(b) It is not possible because when we go along the circular graph the time coordinate some time decreases and other time increases which is not possible. Also at a perticular instant there are two velocities of the body which is not possible.

(c) It is not possible because the speed can’t be negative

(d) It is not possible as the total length of path that is distance can’t decrease with time. 

Illustration 

The position of an object moving along x-axis is given by \displaystyle x\,=\,a+b{{t}^{2}}, where \displaystyle a=\,8.5\,\,m,\,\,b\,=\,2.5\,\,m/s and t is measured in seconds.  What is its velocity at t = 0 s and
t = 2.0 s ? What is the average velocity between t = 2s and t = 4.0 s ?

Solution 

We know that \displaystyle v\,=\,\frac{{dx}}{{dt}}

On differentiating w.r.t. t, we have

\displaystyle v\,=\,\frac{d}{{dt}}\left( {a\,+\,b{{t}^{2}}} \right)=2bt\,\,=\,\,5t\,\,m/s\,\,\,\left[ {\because \,\,\,b\,=\,2.5\,\,m} \right]

At \displaystyle t\,=\,0,\,\,v\,=\,0,\,\,t=2 and \displaystyle v\,=\,10\,\,m/s

Average velocity \displaystyle =\,\frac{{x\,\left( 4 \right)-x\left( 2 \right)}}{{4-2}}\,=\frac{{a+16b-a-4b}}{2}\,=\,6\times b\,=\,6\,\times \,2.5\,\,=\,\,15\,\,m/s

Illustration 

A jogger starts his motion from the position x = 3m and reaches to a position x = 15m and then turns back and move to the position x = 1m. Find the total displacement and the total distance traveled by the jogger

Solution

The initial and final displacements of the jogger are:

\displaystyle {{x}_{i}}=3m;\,\,{{x}_{f}}=1\text{m}

Therefore, displacement \displaystyle \Delta x={{x}_{f}}-{{x}_{i}}=1-3=-2m

distance  = (15 – 3) + (15 – 1) = 12 + 14 = 26m

Note that : Displacement can be negative but distance can never be negative. Displacement is always less than or equal to distance. If the jogger returns back to its starting position, then displacement is zero but distance is still non-zero.

Illustration 

A bird flies toward east at 10 m/s for 100 m. It then turns around and flies at 20 m/s for 15 s.

(a)  Find its average speed

(b)  Find its average velocity

Solution

Let us take the +ve x axis to point east and -ve x ais to point west. Now we need the total time interval. The first part of the journey took

Δt1 = (100  m)/ (10 m/s) = 10 s

and we are given Δt2 = 15 s for the second part. Hence the total time interval is

Δt = Δt1 + Δt2 = 25 s

The bird flies 100 m east and then (20 m/s)x(15 s) = 300 m west

(a)     Average speed = \frac{{Distance}}{{\Delta t}}\,=\frac{{100\,m\,+\,300\,m}}{{25s}}\,=\,16\, m/s

(b)     The net displacement is

Δx = Δx1 + Δx2 = 100 m – 300 m = -200 m

So that vav = \frac{{\Delta x}}{{\Delta t}}\,=\frac{{-200\,m}}{{25\,s}}\,= -8 m/s

The negative sign means that vav is directed toward the west.

Objective Assignment

1.

A toy car travels from A to B at a constant speed  v1 and without stopping at B returns to A at a constant speed v. Then the average speed of the car over the whole journey is

(a) \displaystyle \frac{{{{v}_{1}}+{{v}_{1}}}}{2}           

(b) \displaystyle \frac{{2{{v}_{1}}{{v}_{2}}}}{{{{v}_{1}}+{{v}_{2}}}}     

(c) \displaystyle \sqrt{{{{v}_{1}}{{v}_{2}}}}     

(d) \displaystyle \frac{1}{{\frac{1}{{{{v}_{1}}}}+\frac{1}{{{{v}_{2}}}}}}

Ans.   (b)

2.

If a body covers equal displacements in equal intervals of time, however small these intervals may be, its motion is

(a)  accelerated motion                                    

(b)  uniform motion

(c)  non–uniform motion                                   

(d)  none of the above

Ans.   (b)

3.

A man leaves his house for a cycle ride. He comes back to his house after-an-hour after covering a distance of 1 km. What is his average velocity for the ride?

(a)  \mathbf{0}\,\,\mathbf{km}\,\,{{\mathbf{h}}^{{-\mathbf{1}}}}

(b)  \mathbf{2}\,\,\mathbf{km}\,\,{{\mathbf{h}}^{{-\mathbf{1}}}}    

(c)    \mathbf{2}\,\,\mathbf{km}\,\,{{\mathbf{s}}^{{-\mathbf{1}}}}     

(d)   \frac{\mathbf{1}}{\mathbf{2}}\,\,\mathbf{km}\,\,{{\mathbf{s}}^{{-\mathbf{1}}}}

Ans.   (a)

4.

You observe an object covering distances in the direct proportion to the time elapsed. What conclusion might you draw about its acceleration?

(a)  It is zero               

(b)  It is constant                           

(c)  It is decreasing     

(d)  It is increasing

Ans.   (a)

5.

In any journey, numerical value of ratio of displacement & distance must be

(a) 1          

(b) ≥ 1              

(c) ≤ 1     

(d) zero

Ans.  (c)

6.

In a journey the magnitude of velocity at a certain instant can be more than average speed.

(a) True         

(b) False        

(c) depends on direction of motion    

(d) never

Ans.  (a)

7.

A body with positive displacement cannot have negative velocity

(a) True         

(b) False        

(c) may be True    

(d) None

Ans.  (b)

8.  

Read the statements carefully and choose the correct option

Statement-1 :  If the displacement of the body is zero, the distance covered by it may not be zero.

Statement-2    :  Displacement is a vector quantity and distance is a scalar quantity.

(a) Statement-1 is correct but Statement-2 is wrong

(b) Statement-2 is correct but Statement-1 is wrong

(c) Both the statements are correct

(d) Both the statements are wrong

Ans.  (c)

9. 

A car moves for half of its time at 80 km/h and for rest half of time at 40 km/h.  What is the average speed of the car

(a) 80 km/h

(b) 60 km/h

(c) 40 km/h

(d) 100 km/h

Ans.  (b)

10.

A wheel of radius 1 meter rolls forward half a revolution on a horizontal ground in 2 sec. The magnitude of the average velocity of the point of the wheel initially in contact with the ground is

  (a) \displaystyle \pi                    

 (b) \displaystyle \frac{\pi }{{\sqrt{2}}}

 (c) \displaystyle \frac{{\sqrt{{{{\pi }^{2}}+4}}}}{2}

 (d) \displaystyle \frac{\pi }{2}

Ans.  (c)

Subjective Assignment

1.

A body moving on a circular path, of radius r, has moved through three quarters of its circular path. What are the values of the displacement and the distance travelled by the body at this instant ?

Ans : \displaystyle \text{Displacement = }\sqrt{2}\times r and \displaystyle \text{Distance = }\frac{{\pi r}}{2}

2.

If the displacement of a body is zero, is the distance covered by it necessary to be zero? Comment.

Ans : Not necessary for example over a full circle or any closed path the displacement becomes zero but not distance.

3.

In which of the following examples of motion, can the body be considered approximately a point object?

(a)

A railway carriage moving without jerks between two stations.

(b)

A monkey sitting on the top of a man cycling smoothly on a circular track.

(c)

A spinning cricket ball that turns sharply on hitting the ground.

Ans : (b) and (c)

4.

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11m away from the starting point. At what time the drunkard will fall into the pit?

Ans : 29 sec

5.

An athlete completes one round of a circular track of radius R in 40 seconds. What will be the displacement at the end of 2 min 20 second?

Ans : 2R

6.

The magnitude of the average velocity of a particle is not always equal to its average speed. Why?

Ans : It happens only in uniform motion. If the body is moving over a curved path like a semicircle or any other shape, its displacement and distance will never be same and hence its average velocity and average speed are different.

7.

Can the speed of a body be negative?

Ans : No its a scalar quantity and has magnitude only.

8.

Sameer went on his bike from Delhi to Gurgaon at a speed of 60 km/h and came back at a speed of 40 km/h. What is his average speed for entire journey?

Ans : \displaystyle {{v}_{{av}}}=\frac{{2{{v}_{1}}{{v}_{2}}}}{{{{v}_{1}}+{{v}_{2}}}} = 48km/h

9.

A car moves from A to B with a speed of 30 km h–1 for half time and with 20 km h–1 for remaining half time. What is the average speed of the car?

Ans : \displaystyle {{v}_{{av}}}=\frac{{{{v}_{1}}+{{v}_{2}}}}{2} = 25km h-1.

10.

Two straight lines drawn on the same x-t curve make angles 30° and 60° with time axis. Which line represents greater velocity? What is the ratio of the two velocities?

Ans : The slope (tanq) of x-t graph gives velocity. So more slope means greater velocity .Hence \displaystyle {{v}_{1}}=\tan 30=\frac{1}{{\sqrt{3}}} and \displaystyle {{v}_{2}}=\tan 60=\sqrt{3}.

therefore \displaystyle \frac{{{{v}_{1}}}}{{{{v}_{2}}}}=\frac{{{1}/{{\sqrt{3}}}\;}}{{\sqrt{3}}}=\frac{1}{3}

11.

A body travels a distance s1 with velocity vl and distance s2 with velocity v2 in the same direction. Calculate the average velocity of the body

Ans : \displaystyle {{v}_{{av}}}=\frac{{{{s}_{1}}+{{s}_{2}}}}{{\frac{{{{s}_{1}}}}{{{{v}_{1}}}}+\frac{{{{s}_{2}}}}{{{{v}_{2}}}}}}

12.

The average velocity of a particle is equal to its instantaneous velocity. What is the nature of its displacement-time graph?

Ans : It is a uniform notion so its x-t graph must be a straight line with a constant slope

13.

A body covers one third of its journey with speed u next one third with speed v and the last one-third with speed w. Calculate the average speed of the body during the entire journey.

Ans : \displaystyle {{v}_{{av}}}=\frac{3}{{\frac{1}{{{{v}_{1}}}}+\frac{1}{{{{v}_{2}}}}+\frac{1}{{{{v}_{3}}}}}}

14.

Shyam goes to college with his sister Shreya in their own car. The college is about 10 km from their home. They drive on alternate days. Shreya is a very careful driver, but Shyamdrives rashly. He takes 3 minutes lesser than Shreya in reaching the college.Shreya advises Shyam to drive safely, but he hardly listens.

(a)

What values are displayed by Shreya ? Do you agree with her?

(b)

What is the difference between average speeds of Shyam and Shreya if latter takes 15minutes to drive to the college?

Ans : Difference = 10km/h.

15.

If position (in meter) of particle is given by \displaystyle x={{t}^{2}}+5t+3 find

(a)

Velocity of the particle at t = 3 s and

(b)

Average velocity of the particle between t = 1s to t = 3s

Ans :

(a) \displaystyle v=\frac{{dx}}{{dt}}=11\text{ m/sec}

(b) vav = 9m/sec

16.

The position of an object moving along x-axis is given by \displaystyle x\,=\,a\,+\,b{{t}^{2}},  where a = 8.5 m, b = 2,5 ms–2 and t is measured in seconds.

(a) What is its velocity at t = 0 s and t = 2 s ?

(b) What is the average velocity between t = 2 s and t=4s?

Ans : (a)  v(0) = 0 , v(2) = 10 m/sec ,

          (b) 15 m/sec

17.

Look at the graphs (a) and (d) carefully and state, with reasons, which of these cannot possibly represent one dimensional motion of a particle?

Ans : 

(a) there are two positions at the same time so not possible

(b) there are two velocities at the same time so not possible

(c) speed cannot be negative so not possible

(d) Total length of path always increases with time but in graph it is decreasing also so this graph is not possible

 

18.

A man starts driving his Kinetic Honda from home at 9.30 am and drives with a speed of 20 km/h along a straight road upto his office which is 10 km away from his home. He stays upto 4.30 pm in the office and returns home .on the same road driving his Kinetic Honda with speed of 10 km/h. Draw a position-time, graph of the motion of the man.

Ans : 

Quiz

5
Created by physicscart

Displacement, Distance, Velocity, Speed (Basic Level Quiz)

Basic Quiz On Kinematics' quantities

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1. The displacement of a body is given by 2s = gt^2 where g is a constant. The velocity of the body at any time t is

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2. The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The  distance travelled by the  particle in four seconds is

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3. The area under acceleration-time graph gives

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4. A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of 4 secs. The ball was thrown with the velocity of

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5. A tiger chases a deer 30 m ahead of it and gains 3 metre in 5 second after the chase began. The distance gained by the tiger in 10 second is

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6. A person travels along a straight road for half the distance with velocity  and the remaining half distance with velocity  The average velocity is given by

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7. Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s and 15 m/s. The time of crossing is

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8. The initial velocity of the particle is 10\,\,m/\sec and its retardation is 2m{{\sec }^{2}}. The distance moved by the particle in 5th  second of its motion is

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9. A person moves 30 m north and then 20 m towards east and finally 30\sqrt{2} m in south-west direction. The displacement of the person from the origin will be

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10. A blind person after walking 10 steps in one direction, each of length 80 cm, turns randomly to the left or to right by 90º. After walking a total of 40 steps, the maximum displacement of the person from its starting point can be

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